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Thanks Carl yes that was an obvious blunder on my part. As I was
thinking about this I began imagining the pendulum dropped at the 90-deg
mark to calculate v at the bottom, and of course the value of T in that
case doesn't go as √L/g. I should have left the question as just v at
the bottom. Both the value of v and T are irrelevant to the question at
hand, which is a description of the motion in the two reference frames.
I think the elevator frame of reference seems pretty straightforward
(UCM). It's the ground frame I'm still wondering about.
Stefan Jeglinski
On 1/6/25 7:13 AM, Carl Mungan via Phys-l wrote:
I think the problem is indeterminate because period is independent ofamplitude (for small oscillations). The speed of the bob at the instant the
cable breaks is thus unknown. Call it V.
amplitude before cutting the cable. Here the length of the string is L = g
V is given by sqrt[2gL(1-cosA)] where A is the (unknown) angular
(T/2*pi)^2 which is known.
elevator) with period 2*pi*L/V.
After cutting, the bob will go around in a circle (relative to the
problem as posed:
On Jan 6, 2025, at 12:27 AM, stefan jeglinski<jeglin@4pi.com> wrote:
Happy New Year, I need help sorting out my thinking on this one. The
cab hangs from the ceiling of the cab on a string. The pendulum is set to
"An elevator cab is suspended from a steel cable. A pendulum inside the
swinging and has a period T while the elevator cab is stationary. Suddenly,
the steel cable supporting the cab breaks (or is cut) at precisely the
moment when the pendulum bob reaches its *maximum speed*. Describe the
pendulum’s subsequent motion from the point of view of an observer in the
elevator and also of an observer on the ground. What is the period of the
pendulum as the cab falls?"
allows the pendulum to swing outside of the elevator while it's falling and
(We imagine that the elevator roof has a slot or some opening which
then back in. The pivot point is some frictionless shaft bearing that
allows the pendulum to swing in a complete plane)
The bob drops like every other part of the elevator but it has a horizontal
Me:
Elevator:
When the cable breaks everything goes into free fall (“no gravity”).
speed at the moment of the break. The bob moves to the side as it drops in
such a way that the original tension at the break is intact and the string
stays taut at length L (if the bob was/freely/moving its distance from its
pivot would be > L); thus tension is maintained and the bob moves in
uniform circular motion with a tangential speed v = sqrt(2gL).
can’t go slack for one observer and not the other (yes?); however, the
Ground:
Everything about the pendulum must/look/the same – the pendulum string
bob’s path doesn’t look like a circle from the ground – the bob follows a
vertical cycloid that accelerates down. Punchline: an accelerating cycloid
means the bob is under a non-uniform tension.
a value of g for which the pendulum string doesn’t break for the elevator
This is my key issue: if this analysis is correct then we could choose
observer but could break for the ground observer. Or maybe my analysis is
incorrect.
period" T ~ sqrt(L/g) goes away (infinity for g = 0), the pendulum still
PS the “period” question is interesting. Although the “restoring
has a period due to circular (or cycloidal) motion.
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Carl E. Mungan, Professor of Physics, 410-293-6680
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