Re: L2-"Negotiating" a curve.

[Ludwik Kowalski <KowalskiL@MAIL.MONTCLAIR.EDU>]

I agree. But how to explain this Ffx component? Why is
it directed to the left? The wheel moves along the y axis
and sliding friction force must be along the -y. The front
wheel orientation should have not affect this, unless that
wheel is already on the left side of the y axis. Then we
have a net torque.

Bob Sciamanda wrote:

> > . . . How come
> > that by turning the front wheel to the left the vector sum of
> > Fr+Fl+Ff becomes the centripetal force directed to the left
> > (and equal to m*v^2/R )?
>
> You don't mean that; there is still a tangential frictional force
> component (affecting the speed).
> It only takes a COMPONENT of the total force in the "centripetal
> direction" to effect a change of direction; the "other" (tangential)
> component will affect the speed.