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This might be compared to asking, in F=mA, "if F includes the sum of
electrical, gravitational, etc forces and only their (vector)
sum matters
for calculating A, why the partitioning?" Of course it is
because this
partitioning is our way of enabling the calculation of that
sum, but the
resulting A wouldn't care if you used a different
partitioning (taxonomy
of F) so long as you applied the same vector sum.
Bob
Bob Sciamanda (W3NLV)
Physics, Edinboro Univ of PA (em)
trebor@velocity.net
http://www.velocity.net/~trebor
. . .
If the partitioning is totally arbitrary once a specific process and
time-scale is determined, why bother partitioning at all?
. . .
Joel