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Re: Electrostatics problem
From
: John Mallinckrodt <
ajmallinckro@CSUPOMONA.EDU
>
Date
: Fri, 10 Sep 1999 19:13:04 -0800
P.S. Of course, my geometric proof can be easily extended to the unequal
mass case treated by Michael. Simply replace step 3 with the following:
3. From the triangle of forces for body 1, the law of sines says:
sinT1/F = sinT3/(m1*g)
From the triangle of forces for body 2, the law of sines says:
sinT2/F = sinT3/(m2*g)
Thus, sinT1/sinT2 = m2/m1
John Mallinckrodt
mailto:ajm@csupomona.edu
Cal Poly Pomona
http://www.csupomona.edu/~ajm
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