Chronology | Current Month | Current Thread | Current Date |
[Year List] [Month List (current year)] | [Date Index] [Thread Index] | [Thread Prev] [Thread Next] | [Date Prev] [Date Next] |
-----Original Message-----
From: John Mallinckrodt [SMTP:ajmallinckro@CSUPOMONA.EDU]
Sent: Friday, December 03, 1999 6:12 PM
To: PHYS-L@lists.nau.edu
Subject: Re: Rotation problem
I'm not totally that I understand what problem you are trying to address
with your ad hoc rule (and I don't have a copy of the text), but perhaps
the following will help:
Suppose the "H" is made of 3 identical rods each with mass M and length L.
If your "system" is the two nonaxial rods, then the mass of the system is
2M and the center of mass falls by 3L/4. If your system is all three
rods then the mass of the system is 3M and the center of mass falls by
L/2. In *either* case, the gravitational potential energy decreases by
3MgL/2 and that energy shows up as rotational energy of (1/2)Iw^2 =
(1/2)(4ML^2/3)w^2 giving w = (3/2)(g/L)^(1/2).
John
On Fri, 3 Dec 1999, Lemmerhirt, Fred wrote:
There is an old familiar rotation problem with which I am currentlyuneasy,
and about which I am hoping to get some advice. It involves an H-shapedalong
"frame" falling from a horizontal to a vertical position about an axis
one side of the H. In Halliday, Resnick & Walker's Fundamentals, 5thed.,
it is Problem 83 in Chapter 11. In order to solve for the angular speedin
the vertical position by a simple energy method it seems necessary tonothing
introduce an ad hoc rule something like: "Any mass that contributes
to the rotational inertia should be excluded from the center-of-massthis
calculation." (Such a rule is not needed if the analysis is done for a
parallel axis a distance x along the crossbar of the H and then x is set
equal to zero.) Has anyone developed a satisfying way of dealing with
problem? (Or can someone tell me that I'm just being obtuse andoverlooking
something fundamental?)
John Mallinckrodt mailto:ajm@csupomona.edu
Cal Poly Pomona http://www.csupomona.edu/~ajm