Re: A weighty subject

[Bob Sciamanda <trebor@VELOCITY.NET>]

What am I, your TA?    :)   OK ...

b) Scale reading = S =F_g + mv^2/R . . .

 From     GM^2/16R^2 = Mv^2/2R . . . v^2 = GM/8R . . .

Combining,
S = (8/9 +1/8) GMm/R^2 = (73/72)*(GMm/R^2)

c) free fall acc rel to planet SURFACE :  a = (73/72)*(GM/R^2)

but if you mean a rel to planet CM, then:

a = (137/144)*(GM/R^2)

I hope I transcribed my sloppy notes correctly!
(When's TA pay time?)

Bob

Bob Sciamanda (W3NLV)
Physics, Edinboro Univ of PA (em)
trebor@velocity.net
http://www.velocity.net/~trebor

----- Original Message -----
From: John Mallinckrodt <ajmallinckro@CSUPOMONA.EDU>
To: <PHYS-L@lists.nau.edu>
Sent: Friday, October 15, 1999 1:43 PM
Subject: Re: A weighty subject


> On Fri, 15 Oct 1999, Bob Sciamanda wrote:
>
> > OK, I'll rush in and do what looks simple and non-controversial,
namely
> > part a):
> >
> > F_g = GMm/R^2(1-1/9) = (GMm/R^2)*(8/9) , directed toward the center of
the
> > closest planet.  Next!
>
> Next?  O.K. Your next assignment is to complete the problem.  ;-)
>
> John