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Today's Topics:
1. Re: [**External**] Re: [**External**] Re: pendulum in free
fall (Philip Keller)
2. Re: [**External**] Re: pendulum in free fall (John Welch)
----------------------------------------------------------------------
Message: 1
Date: Mon, 6 Jan 2025 11:03:35 -0500
From: Philip Keller <pkeller@holmdelschools.org>
To: Phys-L@phys-l.org
Subject: Re: [Phys-L] [**External**] Re: [**External**] Re: pendulum
in free fall
Message-ID:
<CAMEjEfMJaFN5XA5b4px7PYRXkUdD=
B89nz3unB093x_mMGPw9g@mail.gmail.com>
Content-Type: text/plain; charset="UTF-8"
I am still running it in Windows 11. We had to update a few years back. It
makes me sad to watch as this amazing tool slowly fades into obscurity...
On Mon, Jan 6, 2025 at 10:01?AM stefan jeglinski <jeglin@4pi.com> wrote:
Nice. That's the accelerating cycloid as I called it. This gets at myable
question:
There's a string that ultimately causes that motion of the bob. At some
point in time, it seems like the tension in the string would be high
enough to break the string. Meanwhile, in the elevator frame, the bob is
merely executing UCM forever...
Does IP still exist any more or still run in modern Windows? I thought
it was no longer developed.
Stefan Jeglinski
On 1/6/25 9:45 AM, Philip Keller via Phys-l wrote:
I was able to simulate this in Interactive Physics. In the elevatorframe,
it is just a vertical circle, as expected. But I would not have been
here:to guess the path in the stationary frame! I took a picture of it
https://docs.google.com/document/d/1SCH65itX6r2ltxAczJL1eJAkpgIYudhbU-noDJ-XXSQ/edit?usp=sharing
(and--
(Btw, this is where Interactive Physics stands out from Phet and others
it took just a few minutes to get this running.)don't
On Mon, Jan 6, 2025 at 9:10?AM Carl Mungan via Phys-l <
phys-l@mail.phys-l.org> wrote:
UCM about a quadratically increasing y coordinate of the center of the
circle. You could probably graph it in Excel.
I don't anyone who makes as big and frequent blunders as myself, so
worry about that! It's a neat problem; where did you get it from?
And yes, we're assuming elevator is so massive compared to the bob
wrote:assuming a massless string) that elevator does not deflect from its
vertical fall due to motion of bob.
On Mon, Jan 6, 2025 at 9:05?AM stefan jeglinski<jeglin@4pi.com>
that90-deg
Thanks Carl yes that was an obvious blunder on my part. As I was
thinking about this I began imagining the pendulum dropped at the
mark to calculate v at the bottom, and of course the value of T in
atcase doesn't go as ?L/g. I should have left the question as just v at
the bottom. Both the value of v and T are irrelevant to the question
frames.hand, which is a description of the motion in the two reference
ofI think the elevator frame of reference seems pretty straightforward
(UCM). It's the ground frame I'm still wondering about.
Stefan Jeglinski
On 1/6/25 7:13 AM, Carl Mungan via Phys-l wrote:
I think the problem is indeterminate because period is independent
instantamplitude (for small oscillations). The speed of the bob at the
Lthe
cable breaks is thus unknown. Call it V.
V is given by sqrt[2gL(1-cosA)] where A is the (unknown) angularamplitude before cutting the cable. Here the length of the string is
=wrote:
g
(T/2*pi)^2 which is known.
After cutting, the bob will go around in a circle (relative to theelevator) with period 2*pi*L/V.
On Jan 6, 2025, at 12:27 AM, stefan jeglinski<jeglin@4pi.com>
The
Happy New Year, I need help sorting out my thinking on this one.
setproblem as posed:the
"An elevator cab is suspended from a steel cable. A pendulum inside
cab hangs from the ceiling of the cab on a string. The pendulum is
tothe
swinging and has a period T while the elevator cab is stationary.Suddenly,
the steel cable supporting the cab breaks (or is cut) at precisely
themoment when the pendulum bob reaches its *maximum speed*. Describe
fallingthependulum?s subsequent motion from the point of view of an observer in
theelevator and also of an observer on the ground. What is the period of
pendulum as the cab falls?"
allows the pendulum to swing outside of the elevator while it's(We imagine that the elevator roof has a slot or some opening which
gravity?).and
then back in. The pivot point is some frictionless shaft bearing that
allows the pendulum to swing in a complete plane)
Me:
Elevator:
When the cable breaks everything goes into free fall (?no
dropsThe bob drops like every other part of the elevator but it has ahorizontal
speed at the moment of the break. The bob moves to the side as it
fromin
such a way that the original tension at the break is intact and thestring
stays taut at length L (if the bob was/freely/moving its distance
thestringits
pivot would be > L); thus tension is maintained and the bob moves in
uniform circular motion with a tangential speed v = sqrt(2gL).
Ground:
Everything about the pendulum must/look/the same ? the pendulum
can?t go slack for one observer and not the other (yes?); however,
analysisfollows abob?s path doesn?t look like a circle from the ground ? the bob
choosevertical cycloid that accelerates down. Punchline: an acceleratingcycloid
means the bob is under a non-uniform tension.
This is my key issue: if this analysis is correct then we could
elevatora value of g for which the pendulum string doesn?t break for the
observer but could break for the ground observer. Or maybe my
is
stillincorrect.
period" T ~ sqrt(L/g) goes away (infinity for g = 0), the pendulumPS the ?period? question is interesting. Although the ?restoring
21402-1363has a period due to circular (or cycloidal) motion.21402-1363
_______________________________________________-----
Forum for Physics Educators
Phys-l@mail.phys-l.org
https://www.phys-l.org/mailman/listinfo/phys-l
Carl E. Mungan, Professor of Physics, 410-293-6680
U.S. Naval Academy Mailstop 9c, 572C Holloway Rd, Annapolis MD
http://usna.edu/Users/physics/mungan/_______________________________________________
_______________________________________________
Forum for Physics Educators
Phys-l@mail.phys-l.org
https://www.phys-l.org/mailman/listinfo/phys-l
Forum for Physics Educators
Phys-l@mail.phys-l.org
https://www.phys-l.org/mailman/listinfo/phys-l
--
Carl E. Mungan, Professor of Physics, 410-293-6680
U.S. Naval Academy Mailstop 9c, 572C Holloway Rd, Annapolis MD
_______________________________________________http://usna.edu/Users/physics/mungan/_______________________________________________
_______________________________________________
Forum for Physics Educators
Phys-l@mail.phys-l.org
https://www.phys-l.org/mailman/listinfo/phys-l
Forum for Physics Educators
Phys-l@mail.phys-l.org
https://www.phys-l.org/mailman/listinfo/phys-l
Forum for Physics Educators
Phys-l@mail.phys-l.org
https://www.phys-l.org/mailman/listinfo/phys-l
------------------------------
Message: 2
Date: Mon, 6 Jan 2025 08:23:51 -0800
From: John Welch <jj@johnw.org>
To: Phys-L@phys-l.org
Subject: Re: [Phys-L] [**External**] Re: pendulum in free fall
Message-ID:
<CAPbf24DUB4v+q=
Ps2k9mHL5+57T3xqDhAWQmLftRbiexSOi_yQ@mail.gmail.com>
Content-Type: text/plain; charset="UTF-8"
I think your paradox about there being a 'g' value that would break the
string in one frame but not the other is resolved if you see that the speed
of the ucm will increase with g also and so cause the string to break as
well in the elevator frame.
On Mon, Jan 6, 2025, 7:01?AM stefan jeglinski <jeglin@4pi.com> wrote:
Nice. That's the accelerating cycloid as I called it. This gets at myable
question:
There's a string that ultimately causes that motion of the bob. At some
point in time, it seems like the tension in the string would be high
enough to break the string. Meanwhile, in the elevator frame, the bob is
merely executing UCM forever...
Does IP still exist any more or still run in modern Windows? I thought
it was no longer developed.
Stefan Jeglinski
On 1/6/25 9:45 AM, Philip Keller via Phys-l wrote:
I was able to simulate this in Interactive Physics. In the elevatorframe,
it is just a vertical circle, as expected. But I would not have been
here:to guess the path in the stationary frame! I took a picture of it
https://docs.google.com/document/d/1SCH65itX6r2ltxAczJL1eJAkpgIYudhbU-noDJ-XXSQ/edit?usp=sharing
(and--
(Btw, this is where Interactive Physics stands out from Phet and others
it took just a few minutes to get this running.)don't
On Mon, Jan 6, 2025 at 9:10?AM Carl Mungan via Phys-l <
phys-l@mail.phys-l.org> wrote:
UCM about a quadratically increasing y coordinate of the center of the
circle. You could probably graph it in Excel.
I don't anyone who makes as big and frequent blunders as myself, so
worry about that! It's a neat problem; where did you get it from?
And yes, we're assuming elevator is so massive compared to the bob
wrote:assuming a massless string) that elevator does not deflect from its
vertical fall due to motion of bob.
On Mon, Jan 6, 2025 at 9:05?AM stefan jeglinski<jeglin@4pi.com>
that90-deg
Thanks Carl yes that was an obvious blunder on my part. As I was
thinking about this I began imagining the pendulum dropped at the
mark to calculate v at the bottom, and of course the value of T in
atcase doesn't go as ?L/g. I should have left the question as just v at
the bottom. Both the value of v and T are irrelevant to the question
frames.hand, which is a description of the motion in the two reference
ofI think the elevator frame of reference seems pretty straightforward
(UCM). It's the ground frame I'm still wondering about.
Stefan Jeglinski
On 1/6/25 7:13 AM, Carl Mungan via Phys-l wrote:
I think the problem is indeterminate because period is independent
instantamplitude (for small oscillations). The speed of the bob at the
Lthe
cable breaks is thus unknown. Call it V.
V is given by sqrt[2gL(1-cosA)] where A is the (unknown) angularamplitude before cutting the cable. Here the length of the string is
=wrote:
g
(T/2*pi)^2 which is known.
After cutting, the bob will go around in a circle (relative to theelevator) with period 2*pi*L/V.
On Jan 6, 2025, at 12:27 AM, stefan jeglinski<jeglin@4pi.com>
The
Happy New Year, I need help sorting out my thinking on this one.
setproblem as posed:the
"An elevator cab is suspended from a steel cable. A pendulum inside
cab hangs from the ceiling of the cab on a string. The pendulum is
tothe
swinging and has a period T while the elevator cab is stationary.Suddenly,
the steel cable supporting the cab breaks (or is cut) at precisely
themoment when the pendulum bob reaches its *maximum speed*. Describe
fallingthependulum?s subsequent motion from the point of view of an observer in
theelevator and also of an observer on the ground. What is the period of
pendulum as the cab falls?"
allows the pendulum to swing outside of the elevator while it's(We imagine that the elevator roof has a slot or some opening which
gravity?).and
then back in. The pivot point is some frictionless shaft bearing that
allows the pendulum to swing in a complete plane)
Me:
Elevator:
When the cable breaks everything goes into free fall (?no
dropsThe bob drops like every other part of the elevator but it has ahorizontal
speed at the moment of the break. The bob moves to the side as it
fromin
such a way that the original tension at the break is intact and thestring
stays taut at length L (if the bob was/freely/moving its distance
thestringits
pivot would be > L); thus tension is maintained and the bob moves in
uniform circular motion with a tangential speed v = sqrt(2gL).
Ground:
Everything about the pendulum must/look/the same ? the pendulum
can?t go slack for one observer and not the other (yes?); however,
analysisfollows abob?s path doesn?t look like a circle from the ground ? the bob
choosevertical cycloid that accelerates down. Punchline: an acceleratingcycloid
means the bob is under a non-uniform tension.
This is my key issue: if this analysis is correct then we could
elevatora value of g for which the pendulum string doesn?t break for the
observer but could break for the ground observer. Or maybe my
is
stillincorrect.
period" T ~ sqrt(L/g) goes away (infinity for g = 0), the pendulumPS the ?period? question is interesting. Although the ?restoring
21402-1363has a period due to circular (or cycloidal) motion.21402-1363
_______________________________________________-----
Forum for Physics Educators
Phys-l@mail.phys-l.org
https://www.phys-l.org/mailman/listinfo/phys-l
Carl E. Mungan, Professor of Physics, 410-293-6680
U.S. Naval Academy Mailstop 9c, 572C Holloway Rd, Annapolis MD
http://usna.edu/Users/physics/mungan/_______________________________________________
_______________________________________________
Forum for Physics Educators
Phys-l@mail.phys-l.org
https://www.phys-l.org/mailman/listinfo/phys-l
Forum for Physics Educators
Phys-l@mail.phys-l.org
https://www.phys-l.org/mailman/listinfo/phys-l
--
Carl E. Mungan, Professor of Physics, 410-293-6680
U.S. Naval Academy Mailstop 9c, 572C Holloway Rd, Annapolis MD
_______________________________________________http://usna.edu/Users/physics/mungan/_______________________________________________
_______________________________________________
Forum for Physics Educators
Phys-l@mail.phys-l.org
https://www.phys-l.org/mailman/listinfo/phys-l
Forum for Physics Educators
Phys-l@mail.phys-l.org
https://www.phys-l.org/mailman/listinfo/phys-l
Forum for Physics Educators
Phys-l@mail.phys-l.org
https://www.phys-l.org/mailman/listinfo/phys-l
------------------------------
Subject: Digest Footer
_______________________________________________
Forum for Physics Educators
Phys-l@mail.phys-l.org
https://www.phys-l.org/mailman/listinfo/phys-l
------------------------------
End of Phys-l Digest, Vol 240, Issue 4
**************************************