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First, let's replace the insulating dielectric by a conducting dielectric;
that is, we build a three-plate capacitor as follows:
P1 P2 P3
P1 P2 P3
P1 P2 P3
wwwwwwwP1 P2 P3wwwwww
P1 P2 P3
P1 P2 P3
P1 P2 P3
where "w" indicates a wire, and P2 is the "dielectric" plate. The
advantage of this scheme is that we can unambiguously talk about the
voltage on P2.
Metal has effectively an infinite dielectric constant, but as long as P2 is
separated from P1 and P3 by an air gap (or other insulator), the
combination of insulator plus P2 makes a fine dielectric, ...
1.1) The first thing to notice is that even if there were a huge net Q on
P2, it would have no effect on the operation of the P1/P2 capacitor, which
could still be treated as a two-terminal device, with no change in
capacitance.
, ... the combination of insulator plus P2 makes a fine dielectric,
increasing the capacitance of the P1/P3 capacitor.